Monday, 18 May 2015

Halogenoalkanes (5) Nucleophilic substitution in primary haloalkanes


#2 Nucleophilic substitution in primary halogenoalkanes.

In a previous post I discussed the basics of this reaction between haloalkanes and aqueous alkali. 

Here is the general reaction scheme:

We can make some criticisms of this image from the web:













The curly arrows are pretty random and sloppily drawn.

We’d like to see them start on a lone pair of the nucleophile and end on a specific positive centre.

We’d also like to see them start on the R—X bond and end as they do on the halide lone pair. 

These generic mechanisms do not indicate anything about the rate at which these reactions proceed. 

Let’s look at another representation of this reaction mechanism from the web:












Now this is the hydrolysis of chloromethane: a primary haloalkane

Note how the arrows are drawn, where they start and where they end: brilliant, copy this!! 

This reaction proceeds in one flowing movement.

The only thing missing is the intermediate transition state.

But this mechanism does show the way in which the geometry of the primary haloalkane ‘flips over’.

There will be more about the consequences of this ‘flip over’ in a later post.

The reaction involves both the haloalkane and the hydroxide ion in the slowest or rate determining step i.e. it is bimolecular. 

The reaction is substitution (S), nucleophilic(N) and bimolecular(2)

That’s why it is called an Sn2 reaction!!

Of course the orientation of the attacking group has to be right too. 

The stereo chemistry of this reaction is important.

The hydroxide ion attacks from the opposite side to the leaving group the chloride (halide) ion. 

So what about the intermediate transition state?

Let’s look at another image from the web (from chemguide) to show this transition state:




















The thing here is to see that the transition state is negatively charged

We write the transition state in square brackets.

I prefer to see curly arrows in red, unless it is on an exam paper, there’s a long historic reason for me saying that that I shall talk about on this blog sometime. 

The other striking geometry is that the transition state has five covalent bonds and the central structure of it is planar.

What is the CH3-C-H bond angle in the transition state?

Two of the bonds in the transition state are partial, one forming as one breaks, hence the use of dotted lines to show this feature. 

The transition state then is a temporary structure with a half life of around 10—12 seconds.

Primary haloalkanes hydrolyse by this mechanism because there are insufficient methyl groups on the primary carbon to stabilise a carbocation as an intermediate structure. 

In my next post, I’ll discuss hydrolysis of tertiary halogenoalkanes

No comments:

Post a Comment

Popular Posts