Tuesday 2 May 2017

Transition metals: Complex ions and colour

Edexcel A level Chemistry (2017)
Topic 15A: Principles of transition metal chemistry
Here are the learning objectives relating to the colour of complex ions:

15/7. To know that transition metals form coloured ions in solution.

15/8. To understand that the colour of aqueous ions, and other complex ions, results from the splitting of the energy levels of the d-orbitals by ligands.

15/9. To understand why there is a lack of colour in some aqueous ions and other complex ions.
15/10. To understand that colour changes in transition metal ions may arise as a result of changes in:
i) oxidation number,
ii) ligand,
iii) coordination number.


Transition metal complex ions and the origin of colour.

One of the distinctive features of transition metal complex ions is that they are usually coloured.

Here are some typical complex ions and their colours:

Name
Formula
Colour
Coordination number
Shape
Tetraammine copper (II)
[Cu(NH3)4]2+
deep blue
4
square planar
Tetrachloro cuprate(II)
[CuCl4]2—
yellow green
4
tetrahedral
Hexaaqua
cobalt(II)
[Co(H2O)]2+
red
6
octahedral

Question: What process causes the colour of these ions?

The complex ions are coloured because they absorb light and we see the light that is not absorbed but transmitted. 


Here is a table that shows you the colour and wavelengths of light absorbed and transmitted by complex ions.

The wavelength (nm) of the transmitted color of the solution.
The transmitted color of the solution.
The complementary color of the solution.
400–435
violet
yellowish–green
435-480
blue
yellow
480–490
greenish–blue
orange
490–500
bluish–green
red
500–560
green
purple
560–580
yellowish–green
violet
580–595
yellow
blue
595–610
orange
greenish–blue
610–750
red
bluish–green


The process at the atomic level involves the excitation of electrons in the d orbitals of the complex ion.



It is possible to calculate the energy gap between these d orbitals if we know the wavelength (or frequency) of the light absorbed. 




The table below shows the details of the light absorbed from the visible region to give the colour of transition metal ions.


Colour
Absorbed
Wavelength λ (nm)
Frequency
ν (1014 Hz)
Energy
(kJ.mol—1)
Energy ΔE
(10—19J)
Infrared
1000
3.00
120
1.993
Red
700
4.28
171
2.839
Orange
620
4.84
193
3.205
Yellow
580
5.17
206
3.421
Green
530
5.66
226
3.753
Blue
470
6.38
254
4.218
Violet
420
7.14
285
4.732
Ultra violet
300
10.0
400
6.642

Remember the colour absorbed is complementary to the colour observed.  


So for example a purple coloured ion like manganate(VII) MnO4is actually absorbing green light and ΔE is approx. 3.7  ×  10—19 J.


If there are no d electrons then the ion is colourless and similarly if the d subshells are full there is no chance of a d—d transition and so these ions are also colourless.  

Examples would be the Scandium(III), Sc3+ ion, the Zinc(II), Zn2+ ion and the copper(I), Cuion.


The absorption of light by a complex ion can also be used to calculate the concentration of this ion in solution.



My next post will discuss an experimental approach to this problem.

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